submit
onsubmit时的一个检测函数，可是返回的结果都是true

var check_object1 = new check_Object( " ", " ", " ");
只要上面的参数不为空，就提交了,不知道为什么


////////////////////////////////////////////////////////////

onsubmit= "javascript:return check_addlisting(this.form); "

//check object
function check_Object(typeid,nametext,nameform){
this.typeid = typeid ;
this.nametext = nametext ;
this.nameform = nameform ;

this.get_nameform = function(){
return this.nameform ; //问题可能在这里?

}
this.get_typeid = function(){
return this.typeid ;
}
this.get_nametext = function(){
return this.nametext ;
}

}


//check type
function check_type(check_object_instance){
this.typeid = check_object_instance.get_typeid() ;
this.nameform = check_object_instance.get_nameform() ;
this.nametext = check_object_instance.get_nametext() ;

this.check = function(){
switch(this.typeid){
case "1 ": {//check null
return this.check_null() ;
}
case "2 ":{//check "-1 "
return this.check_any() ;
}
default:{
return false ;
}

}

}

this.check_null = function(){
if(this.nametext.value == " "){
return false ;
}
}
this.check_any = function(){
if(this.nametext.value == "-1 "){
return false ;
}
}
}


//---------------------------------------check
//check addlisting 's form
function check_addlisting(nameform){

var check_object1 = new check_Object( "2 ",nameform.type2,nameform) ;

var check_type1 = new check_type(check_object1) ;

return check_type1.check() ;


return false ;
}

------解决方案--------------------
/**
this.get_nameform = function(){
return this.nameform ; //问题可能在这里?

}
this.get_typeid = function(){
return this.typeid ;
}
this.get_nametext = function(){
return this.nametext ;
}
**/
把上面三句合成一句：return this;//其它属性直接引用，后续处理就是检测数据；
------解决方案--------------------
看不出來.