)×
]+
×2.75+0.125×
+12.5%(362+548×361)÷(362×548-186)
×
+
×
+
×
+…+
×
.解:(1)5÷[(35%-
)×
]+
,=5÷[(
-
)×
]+
,=5÷[(
-
)×
]+
,=5÷[
×
]+
,=5÷

,=25+
,=25
;(2)
×2.75+0.125×
+12.5%,=0.125×2.75+0.125×4.25+0.125,
=(2.75+4.25+1)×0.125,
=8×0.125,
=1;
(3)(362+548×361)÷(362×548-186),
=[362+548×(362-1)]÷(362×548-186),
=[362-548+548×362]÷(362×548-186),
=(362×548-186)÷(362×548-186),
=1;
(4)
×
+
×
+
×
+…+
×
,=
×(1-
)+
×(
-
)+
×(
-
)+…+
×(
-
),=
×(1-
+
-
+
-
+…+
-
),=
×(1-
),=
.分析:(1)按运算顺序计算,先算小括号里的,再算中括号里的,最后算括号外的;
(2)根据数字特点,把分数化为小数,然后用乘法分配律的逆运算简算;
(3)此题如果直接计算,会较麻烦,所以要寻找简便的算法.前后两个括号内的数字有一定特点,通过变形,前后两个括号内的算式相同,故答案为1;
(4)此题设计较新颖,如果直接计算会很麻烦,这就要寻求简便的算法,可先把原式变为:
×(1-
)+
×(
-
)+
×(
-
)+…+
×(
-
),这样就很明朗了.点评:此题考查了运算顺序,以及运用所学知识灵活巧算的能力.