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能用简便方法的用简便方法.(1)710+(45-14)÷234 (2)[35-(916-25)]×117(3)20.07×1994-19.93×2007 (4)54÷[6.3-134×(123+192

编辑:chaxungu时间:2026-04-27 13:18:25分类:小学数学题库

能用简便方法的用简便方法.
(1)
7
10
+(
4
5
-
1
4
)÷2
3
4

(2)[
3
5
-(
9
16
-
2
5
)]×1
1
7

(3)20.07×1994-19.93×2007
(4)54÷[6.3-1
3
4
×(1
2
3
+
19
21
)]
(5)(1+
1
2
+
1
3
+
1
4
)×(
1
2
+
1
3
+
1
4
+
1
5
)-(1+
1
2
+
1
3
+
1
4
+
1
5
)×(
1
2
+
1
3
+
1
4
).
(1)
7
10
+(
4
5
-
1
4
)÷2
3
4
,
=
7
10
+
11
20
÷2
3
4
,
=
7
10
+
1
5
,
=
9
10
;

(2)[
3
5
-(
9
16
-
2
5
)]×1
1
7
,
=[
3
5
-
9
16
+
2
5
]×1
1
7
,
=[
3
5
+
2
5
-
9
16
]×1
1
7
,
=[1-
9
16
]×1
1
7
,
=
7
16
×1
1
7
,
=
1
2
;

(3)20.07×1994-19.93×2007,
=20.07×1994-1993×20.07,
=20.07×,
=20.07×1,
=20.07;

(4)54÷[6.3-1
3
4
×(1
2
3
+
19
21
)],
=54÷[6.3-1
3
4
×
18
7
],
=54÷[6.3-4.5],
=54÷1.8,
=30;

(5)令
1
2
+
1
3
+
1
4
=a,
1
2
+
1
3
+
1
4
+
1
5
=b;
原式=(1+a)?b-(1+b)?a=b-a;
所以,(1+
1
2
+
1
3
+
1
4
)×(
1
2
+
1
3
+
1
4
+
1
5
)-(1+
1
2
+
1
3
+
1
4
+
1
5
)×(
1
2
+
1
3
+
1
4
)
=(
1
2
+
1
3
+
1
4
+
1
5
)-(
1
2
+
1
3
+
1
4
),
=
1
5
.