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用递等式计算0.36×1147+1337÷791859-(7513-213)-813÷120.56÷[(3.6×512-1.5)×4.4+5.6].

编辑:chaxungu时间:2026-04-27 13:18:52分类:小学数学题库

用递等式计算
0.36×11
4
7
+13
3
7
÷
7
9

18
5
9
-(7
5
13
-2
1
3
)-
8
13
÷
1
2

0.56÷[(3.6×
5
12
-1.5)×4.4+5.6].(1)0.36×11
4
7
+13
3
7
÷
7
9
,
=
9
25
×
81
7
+
94
7
×
9
7
,
=
729
175
+
846
49
,
5103
1225
+
21150
1225
,
=
26253
1225
,
=21
528
1225
;

(2)18
5
9
-(7
5
13
-2
1
3
)-
8
13
÷
1
2
,
=18
5
9
-5
2
39
-
8
13
×2,
=18
5
9
-5
2
39
-
16
13
,
=18
65
117
-5
6
117
-
144
117
,
=12
32
117
;

(3)0.56÷[(3.6×
5
12
-1.5)×4.4+5.6],
=0.56÷[(1.5-1.5)×4.4+5.6],
=0.56÷[0×4.4+5.6],
=0.56÷5.6,
=0.1.