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用递等式计算.(1)1357+450÷18×25(2)13.7-26.4÷(3)3.6×[2÷(45-0.6)](4)4-[1-(35+14)]÷317.

编辑:chaxungu时间:2026-04-27 13:21:12分类:小学数学题库

用递等式计算.
(1)1357+450÷18×25
(2)13.7-26.4÷(2.6+1.4)
(3)3.6×[2÷(
4
5
-0.6)]
(4)4-[1-(
3
5
+
1
4
)]÷
3
17
.(1)1357+450÷18×25,
=1357+25×25,
=1357+625,
=1982;

(2)13.7-26.4÷(2.6+1.4),
=13.7-26.4÷4,
=13.7-6.6,
=7.1;

(3)3.6×[2÷(
4
5
-0.6)],
=3.6×[2÷0.2],
=3.6×10,
=36;

(4)4-[1-(
3
5
+
1
4
)]÷
3
17
,
=4-[1-
17
20
]÷
3
17
,
=4-
3
20
÷
3
17
,
=4-
17
20
,
=3
3
20
.