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递等式计算. 1224÷36×25-758 132.5-18÷7.5+7.6 12-27+17÷15 [34-(716-14)]×89.

编辑:chaxungu时间:2026-04-27 13:21:22分类:小学数学题库

递等式计算.
1224÷36×25-758132.5-18÷7.5+7.612-
2
7
+
1
7
÷
1
5
[
3
4
-(
7
16
-
1
4
)]×
8
9
.
(1)1224÷36×25-758,
=34×25-758,
=850-758,
=92;

(2)132.5-18÷7.5+7.6,
=132.5-2.4+7.6,
=130.1+7.6,
=137.7;

(3)12-
2
7
+
1
7
÷
1
5
,
=12-
2
7
+
5
7
,
=11
5
7
+
5
7
,
=12
3
7
;

(4)[
3
4
-(
7
16
-
1
4
)]×
8
9
,
=[
3
4
-
3
16
]×
8
9
,
=
9
16
×
8
9
,
=
1
2
.