| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 5 |
第一根绳子截去两次后剩下的米数:x-
| 1 |
| 5 |
| 1 |
| 5 |
| 4 |
| 5 |
| 1 |
| 5 |
第二根绳子截去两次后剩下的米数:x-
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 5 |
=x-
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 25 |
=
| 4 |
| 5 |
| 4 |
| 25 |
因为,
| 4 |
| 5 |
| 1 |
| 5 |
| 4 |
| 5 |
| 4 |
| 25 |
所以,两根剩下的部分相比第二根长,
故选:B.
编辑:chaxungu时间:2026-04-27 14:05:35分类:小学数学题库
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