(1)(27×1
+6
×27)×1.25(2)〔2-(5.55×1
-2
÷0.4)〕÷0.135.解:(1)(27×1
+6
×27)×1.25=(1
+6
)×27×1.25,=8×1.25×27,
=10×27,
=270;
(2)[2-(5.55×1
-2
÷0.4)]÷0.135=[2-(5.55×
-2.7÷0.4)]÷0.135,=[2-(7.4-6.75)]÷0.135,
=[2-0.65]÷0.135,
=1.35÷0.135,
=10.
分析:(1)可运用乘法分配律及交换律计算;
(2)根据四则混合运算的运算顺序计算即可.
点评:当算式中同时含有小数与分数时,要根据式中数据的特点灵活将它们互化后进行计算.