①12×
÷
②(2+
)×18③
×
+
④77×
+23×0.8⑤
÷[(
)×
].解:①12×
÷
=12×
×
,=6;
②(2+
)×18=2×18+
×18,=36+4,
=40;
③
×
+
=
+
,=
;④77×
+23×0.8=77×0.8+23×0.8,
=(77+23)×0.8,
=100×0.8,
=80;
⑤
÷[(
)×
]=
÷[
×
],=
×6,=
.分析:①可根据乘法交换律计算;
②④可根据乘法分配律计算;
③⑤根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的.
点评:完成有关于分数四则混合运算时要细心,注意通分约分.