2007+2007×99
1.5×[0.02÷(2.1-2.09)]
×125×
×821×
+48×12.5%+11×
.解:(1)2007+2007×99,=2007×(1+99),
=2007×100,
=200700;
(2)1.5×[0.02÷(2.1-2.09)],
=1.5×[0.02÷0.01],
=1.5×2,
=3;
(3)
×125×
×8,=(
×8)×(125×
),=2×1,
=2;
(4)21×
+48×12.5%+11×
,=
×(21+48+11),=
×80,=10.
分析:(1)运用乘法分配律解答,
(2)依据四则运算计算方法解答,
(3)运用乘法交换律,以及乘法结合律解答,
(4)运用乘法分配律解答.
点评:本题主要考查学生正确运用四则运算和简便算法的能力.