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用递等式计算. ①960÷30-10 ②56×2÷3031 ③(59+76)×36 ④52-2.5×0.9×4 ⑤78÷[(34-12)÷45].

编辑:chaxungu时间:2026-04-27 13:18:23分类:小学数学题库

用递等式计算.
①960÷30-10②
5
6
×2÷
30
31
③(
5
9
+
7
6
)×36
④52-2.5×0.9×4⑤
7
8
÷[(
3
4
-
1
2
)÷
4
5
].

①960÷30-10,
=32-10,
=22;

②
5
6
×2÷
30
31
,
=
5
3
÷
30
31
,
=
31
18
;

③(
5
9
+
7
6
)×36,
=
5
9
×36+
7
6
×36,
=20+42,
=62;

④52-2.5×0.9×4,
=52-2.5×4×0.9,
=52-10×0.9,
=52-9,
=43;

⑤
7
8
÷[(
3
4
-
1
2
)÷
4
5
],
=
7
8
÷[
1
4
÷
4
5
],
=
7
8
÷
5
16
,
=
14
5
.