=(2,-1),
=(x,-2),
=(3,y),若
∥
,(
+
)⊥(
-
),则x+y的值为________.在线课程5分析:由向量的平行和垂直的充要条件分别可得想,y的值,相加即可得答案.
解答:∵
,∴2×(-2)-(-1)x=0,解得x=4故
=(4,-2),
=(6,-3),
=(-1,-1-y)由
可得
=0,即-6+3+3y=0,解得y=1,故x+y=5
故答案为:5
点评:本题考查向量的基本运算,涉及向量的平行和垂直的充要条件及数量积的运算,属中档题.
编辑:chaxungu时间:2026-04-27 17:09:33分类:高中数学题库
=(2,-1),
=(x,-2),
=(3,y),若
∥
,(
+
)⊥(
-
),则x+y的值为________.在线课程5
,∴2×(-2)-(-1)x=0,解得x=4
=(4,-2),
=(6,-3),
=(-1,-1-y)
可得
=0,即-6+3+3y=0,